(4n^2+16n+64)-112=0

Solution for (4n^2+16n+64)-112=0 equation:

(4n^2+16n+64)-112=0

We get rid of parentheses

4n^2+16n+64-112=0

We add all the numbers together, and all the variables

4n^2+16n-48=0

a = 4; b = 16; c = -48;
Δ = b2-4ac
Δ = 162-4·4·(-48)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-32}{2*4}=\frac{-48}{8}
=-6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+32}{2*4}=\frac{16}{8}
=2
$